(x+3)*(x+4)=(x+1)*(x+2)

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Solution for (x+3)*(x+4)=(x+1)*(x+2) equation: 



(x+3)(x+4)=(x+1)(x+2)

We move all terms to the left:

(x+3)(x+4)-((x+1)(x+2))=0

We multiply parentheses ..

(+x^2+4x+3x+12)-((x+1)(x+2))=0



We calculate terms in parentheses: -((x+1)(x+2)), so:

(x+1)(x+2)

We multiply parentheses ..

(+x^2+2x+x+2)

We get rid of parentheses

x^2+2x+x+2

We add all the numbers together, and all the variables

x^2+3x+2

Back to the equation:

-(x^2+3x+2)



We get rid of parentheses

x^2-x^2+4x+3x-3x+12-2=0

We add all the numbers together, and all the variables

4x+10=0

We move all terms containing x to the left, all other terms to the right

4x=-10

x=-10/4

x=-2+1/2

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