(x+3)*(x-3)-(x+2)*(x)=0

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Solution for (x+3)*(x-3)-(x+2)*(x)=0 equation: 



(x+3)(x-3)-(x+2)(x)=0

We use the square of the difference formula

x^2-(x+2)x-9=0

We multiply parentheses

x^2-x^2-2x-9=0

We add all the numbers together, and all the variables

-2x-9=0

We move all terms containing x to the left, all other terms to the right

-2x=9

x=9/-2

x=-4+1/2

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