(x+3)*(x-7)+(5-x)*(x+4)=10

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Solution for (x+3)*(x-7)+(5-x)*(x+4)=10 equation: 



(x+3)(x-7)+(5-x)(x+4)=10

We move all terms to the left:

(x+3)(x-7)+(5-x)(x+4)-(10)=0

We add all the numbers together, and all the variables

(x+3)(x-7)+(-1x+5)(x+4)-10=0

We multiply parentheses ..

(+x^2-7x+3x-21)+(-1x+5)(x+4)-10=0

We get rid of parentheses

x^2-7x+3x+(-1x+5)(x+4)-21-10=0

We multiply parentheses ..

x^2+(-1x^2-4x+5x+20)-7x+3x-21-10=0

We add all the numbers together, and all the variables

x^2+(-1x^2-4x+5x+20)-4x-31=0

We get rid of parentheses

x^2-1x^2-4x+5x-4x+20-31=0

We add all the numbers together, and all the variables

-3x-11=0

We move all terms containing x to the left, all other terms to the right

-3x=11

x=11/-3

x=-3+2/3

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