(x+3)*(x-7)+(5-x)*(x-4)=10

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Solution for (x+3)*(x-7)+(5-x)*(x-4)=10 equation: 



(x+3)(x-7)+(5-x)(x-4)=10

We move all terms to the left:

(x+3)(x-7)+(5-x)(x-4)-(10)=0

We add all the numbers together, and all the variables

(x+3)(x-7)+(-1x+5)(x-4)-10=0

We multiply parentheses ..

(+x^2-7x+3x-21)+(-1x+5)(x-4)-10=0

We get rid of parentheses

x^2-7x+3x+(-1x+5)(x-4)-21-10=0

We multiply parentheses ..

x^2+(-1x^2+4x+5x-20)-7x+3x-21-10=0

We add all the numbers together, and all the variables

x^2+(-1x^2+4x+5x-20)-4x-31=0

We get rid of parentheses

x^2-1x^2+4x+5x-4x-20-31=0

We add all the numbers together, and all the variables

5x-51=0

We move all terms containing x to the left, all other terms to the right

5x=51

x=51/5

x=10+1/5

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