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(x+3)(x-7)+(5-x)(x-4)=10
We move all terms to the left:
(x+3)(x-7)+(5-x)(x-4)-(10)=0
We add all the numbers together, and all the variables
(x+3)(x-7)+(-1x+5)(x-4)-10=0
We multiply parentheses ..
(+x^2-7x+3x-21)+(-1x+5)(x-4)-10=0
We get rid of parentheses
x^2-7x+3x+(-1x+5)(x-4)-21-10=0
We multiply parentheses ..
x^2+(-1x^2+4x+5x-20)-7x+3x-21-10=0
We add all the numbers together, and all the variables
x^2+(-1x^2+4x+5x-20)-4x-31=0
We get rid of parentheses
x^2-1x^2+4x+5x-4x-20-31=0
We add all the numbers together, and all the variables
5x-51=0
We move all terms containing x to the left, all other terms to the right
5x=51
x=51/5
x=10+1/5
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