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(x+3)+(x+3)=(8x)
We move all terms to the left:
(x+3)+(x+3)-((8x))=0
determiningTheFunctionDomain (x+3)+(x+3)-8x=0
We add all the numbers together, and all the variables
-8x+(x+3)+(x+3)=0
We get rid of parentheses
-8x+x+x+3+3=0
We add all the numbers together, and all the variables
-6x+6=0
We move all terms containing x to the left, all other terms to the right
-6x=-6
x=-6/-6
x=1
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