(x+3)+(y-4)=16

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Solution for (x+3)+(y-4)=16 equation:


Simplifying
(x + 3) + (y + -4) = 16

Reorder the terms:
(3 + x) + (y + -4) = 16

Remove parenthesis around (3 + x)
3 + x + (y + -4) = 16

Reorder the terms:
3 + x + (-4 + y) = 16

Remove parenthesis around (-4 + y)
3 + x + -4 + y = 16

Reorder the terms:
3 + -4 + x + y = 16

Combine like terms: 3 + -4 = -1
-1 + x + y = 16

Solving
-1 + x + y = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + x + 1 + y = 16 + 1

Reorder the terms:
-1 + 1 + x + y = 16 + 1

Combine like terms: -1 + 1 = 0
0 + x + y = 16 + 1
x + y = 16 + 1

Combine like terms: 16 + 1 = 17
x + y = 17

Add '-1y' to each side of the equation.
x + y + -1y = 17 + -1y

Combine like terms: y + -1y = 0
x + 0 = 17 + -1y
x = 17 + -1y

Simplifying
x = 17 + -1y

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