(x+3)+3(x+1)=4(2x-3)+3

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Solution for (x+3)+3(x+1)=4(2x-3)+3 equation: 



(x+3)+3(x+1)=4(2x-3)+3

We move all terms to the left:

(x+3)+3(x+1)-(4(2x-3)+3)=0

We multiply parentheses

(x+3)+3x-(4(2x-3)+3)+3=0

We get rid of parentheses

x+3x-(4(2x-3)+3)+3+3=0



We calculate terms in parentheses: -(4(2x-3)+3), so:

4(2x-3)+3

We multiply parentheses

8x-12+3

We add all the numbers together, and all the variables

8x-9

Back to the equation:

-(8x-9)



We add all the numbers together, and all the variables

4x-(8x-9)+6=0

We get rid of parentheses

4x-8x+9+6=0

We add all the numbers together, and all the variables

-4x+15=0

We move all terms containing x to the left, all other terms to the right

-4x=-15

x=-15/-4

x=3+3/4

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