(x+3)+x+(2x-1)+(x/0.2)=86

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Solution for (x+3)+x+(2x-1)+(x/0.2)=86 equation:



(x+3)+x+(2x-1)+(x/0.2)=86
We move all terms to the left:
(x+3)+x+(2x-1)+(x/0.2)-(86)=0
We add all the numbers together, and all the variables
(x+3)+x+(2x-1)+(+x/0.2)-86=0
We add all the numbers together, and all the variables
x+(x+3)+(2x-1)+(+x/0.2)-86=0
We get rid of parentheses
x+x+2x+x/0.2+3-1-86=0
We multiply all the terms by the denominator
x*0.2+x*0.2+2x*0.2+x+3*0.2-1*0.2-86*0.2=0
We add all the numbers together, and all the variables
x+x*0.2+x*0.2+2x*0.2-16.8=0
Wy multiply elements
x+0.2x+0.2x+0.4x-16.8=0
We add all the numbers together, and all the variables
1.8x-16.8=0
We move all terms containing x to the left, all other terms to the right
1.8x=16.8
x=16.8/1.8
x=9+0.6/1.8

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