(x+3)+x=3(x+1)-5

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Solution for (x+3)+x=3(x+1)-5 equation: 



(x+3)+x=3(x+1)-5

We move all terms to the left:

(x+3)+x-(3(x+1)-5)=0

We add all the numbers together, and all the variables

x+(x+3)-(3(x+1)-5)=0

We get rid of parentheses

x+x-(3(x+1)-5)+3=0



We calculate terms in parentheses: -(3(x+1)-5), so:

3(x+1)-5

We multiply parentheses

3x+3-5

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

2x-(3x-2)+3=0

We get rid of parentheses

2x-3x+2+3=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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