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(x+3)-2(2-5x)=5(x+4)-3
We move all terms to the left:
(x+3)-2(2-5x)-(5(x+4)-3)=0
We add all the numbers together, and all the variables
(x+3)-2(-5x+2)-(5(x+4)-3)=0
We multiply parentheses
(x+3)+10x-(5(x+4)-3)-4=0
We get rid of parentheses
x+10x-(5(x+4)-3)+3-4=0
We calculate terms in parentheses: -(5(x+4)-3), so:We add all the numbers together, and all the variables
5(x+4)-3
We multiply parentheses
5x+20-3
We add all the numbers together, and all the variables
5x+17
Back to the equation:
-(5x+17)
11x-(5x+17)-1=0
We get rid of parentheses
11x-5x-17-1=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3
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