(x+3)-2c-(1-3c)=2

Solution for (x+3)-2c-(1-3c)=2 equation:

Simplifying
(x + 3) + -2c + -1(1 + -3c) = 2

Reorder the terms:
(3 + x) + -2c + -1(1 + -3c) = 2

Remove parenthesis around (3 + x)
3 + x + -2c + -1(1 + -3c) = 2
3 + x + -2c + (1 * -1 + -3c * -1) = 2
3 + x + -2c + (-1 + 3c) = 2

Reorder the terms:
3 + -1 + -2c + 3c + x = 2

Combine like terms: 3 + -1 = 2
2 + -2c + 3c + x = 2

Combine like terms: -2c + 3c = 1c
2 + 1c + x = 2

Add '-2' to each side of the equation.
2 + 1c + -2 + x = 2 + -2

Reorder the terms:
2 + -2 + 1c + x = 2 + -2

Combine like terms: 2 + -2 = 0
0 + 1c + x = 2 + -2
1c + x = 2 + -2

Combine like terms: 2 + -2 = 0
1c + x = 0

Solving
1c + x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1x' to each side of the equation.
1c + x + -1x = 0 + -1x

Combine like terms: x + -1x = 0
1c + 0 = 0 + -1x
1c = 0 + -1x
Remove the zero:
1c = -1x

Divide each side by '1'.
c = -1x

Simplifying
c = -1x