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(x+3)/(2x+1)=3
We move all terms to the left:
(x+3)/(2x+1)-(3)=0
Domain of the equation: (2x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=-1
x!=-1/2
x!=-1/2
x∈R
(x+3)-3*(2x+1)=0
We multiply parentheses
(x+3)-6x-3=0
We get rid of parentheses
x-6x+3-3=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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