(x+3)/(2x+3)=2

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Solution for (x+3)/(2x+3)=2 equation: 



(x+3)/(2x+3)=2

We move all terms to the left:

(x+3)/(2x+3)-(2)=0



Domain of the equation: (2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-3

x!=-3/2

x!=-1+1/2

x∈R



We multiply all the terms by the denominator


(x+3)-2*(2x+3)=0

We multiply parentheses

(x+3)-4x-6=0

We get rid of parentheses

x-4x+3-6=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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