(x+3)/(2x-3)=2

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Solution for (x+3)/(2x-3)=2 equation: 



(x+3)/(2x-3)=2

We move all terms to the left:

(x+3)/(2x-3)-(2)=0



Domain of the equation: (2x-3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=3

x!=3/2

x!=1+1/2

x∈R



We multiply all the terms by the denominator


(x+3)-2*(2x-3)=0

We multiply parentheses

(x+3)-4x+6=0

We get rid of parentheses

x-4x+3+6=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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