(x+3)/2=(5x-12)/6

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Solution for (x+3)/2=(5x-12)/6 equation: 



(x+3)/2=(5x-12)/6

We move all terms to the left:

(x+3)/2-((5x-12)/6)=0

We calculate fractions


x/()+(-((5x-12)*2)/()=0



We calculate terms in parentheses: +(-((5x-12)*2)/(), so:

-((5x-12)*2)/(

We multiply all the terms by the denominator


-((5x-12)*2)



We calculate terms in parentheses: -((5x-12)*2), so:

(5x-12)*2

We multiply parentheses

10x-24

Back to the equation:

-(10x-24)



We get rid of parentheses

-10x+24

Back to the equation:

+(-10x+24)



We get rid of parentheses

x/()-10x+24=0

We multiply all the terms by the denominator


x-10x*()+24*()=0

We add all the numbers together, and all the variables

x-10x*()=0

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