(x+3)/2=(x-3)/6

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Solution for (x+3)/2=(x-3)/6 equation: 



(x+3)/2=(x-3)/6

We move all terms to the left:

(x+3)/2-((x-3)/6)=0

We calculate fractions


x/()+(-((x-3)*2)/()=0



We calculate terms in parentheses: +(-((x-3)*2)/(), so:

-((x-3)*2)/(

We multiply all the terms by the denominator


-((x-3)*2)



We calculate terms in parentheses: -((x-3)*2), so:

(x-3)*2

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

-2x+6

Back to the equation:

+(-2x+6)



We get rid of parentheses

x/()-2x+6=0

We multiply all the terms by the denominator


x-2x*()+6*()=0

We add all the numbers together, and all the variables

x-2x*()=0

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