(x+3)/2=(x-4)/3

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Solution for (x+3)/2=(x-4)/3 equation:



(x+3)/2=(x-4)/3
We move all terms to the left:
(x+3)/2-((x-4)/3)=0
We calculate fractions
x/()+(-((x-4)*2)/()=0
We calculate terms in parentheses: +(-((x-4)*2)/(), so:
-((x-4)*2)/(
We multiply all the terms by the denominator
-((x-4)*2)
We calculate terms in parentheses: -((x-4)*2), so:
(x-4)*2
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
We get rid of parentheses
-2x+8
Back to the equation:
+(-2x+8)
We get rid of parentheses
x/()-2x+8=0
We multiply all the terms by the denominator
x-2x*()+8*()=0
We add all the numbers together, and all the variables
x-2x*()=0

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