(x+3)/2=(x-5)/6

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Solution for (x+3)/2=(x-5)/6 equation: 



(x+3)/2=(x-5)/6

We move all terms to the left:

(x+3)/2-((x-5)/6)=0

We calculate fractions


x/()+(-((x-5)*2)/()=0



We calculate terms in parentheses: +(-((x-5)*2)/(), so:

-((x-5)*2)/(

We multiply all the terms by the denominator


-((x-5)*2)



We calculate terms in parentheses: -((x-5)*2), so:

(x-5)*2

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

-2x+10

Back to the equation:

+(-2x+10)



We get rid of parentheses

x/()-2x+10=0

We multiply all the terms by the denominator


x-2x*()+10*()=0

We add all the numbers together, and all the variables

x-2x*()=0

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