(x+3)/3=(2x-1)/7

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Solution for (x+3)/3=(2x-1)/7 equation: 



(x+3)/3=(2x-1)/7

We move all terms to the left:

(x+3)/3-((2x-1)/7)=0

We calculate fractions


x/()+(-((2x-1)*3)/()=0



We calculate terms in parentheses: +(-((2x-1)*3)/(), so:

-((2x-1)*3)/(

We multiply all the terms by the denominator


-((2x-1)*3)



We calculate terms in parentheses: -((2x-1)*3), so:

(2x-1)*3

We multiply parentheses

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

-6x+3

Back to the equation:

+(-6x+3)



We get rid of parentheses

x/()-6x+3=0

We multiply all the terms by the denominator


x-6x*()+3*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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