(x+3)/3=(x+5)/1

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Solution for (x+3)/3=(x+5)/1 equation:



(x+3)/3=(x+5)/1
We move all terms to the left:
(x+3)/3-((x+5)/1)=0
We calculate fractions
x/()+(-((x+5)*3)/()=0
We calculate terms in parentheses: +(-((x+5)*3)/(), so:
-((x+5)*3)/(
We multiply all the terms by the denominator
-((x+5)*3)
We calculate terms in parentheses: -((x+5)*3), so:
(x+5)*3
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
We get rid of parentheses
-3x-15
Back to the equation:
+(-3x-15)
We get rid of parentheses
x/()-3x-15=0
We multiply all the terms by the denominator
x-3x*()-15*()=0
We add all the numbers together, and all the variables
x-3x*()=0

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