(x+3)/3=10-(x+6)/2

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Solution for (x+3)/3=10-(x+6)/2 equation:



(x+3)/3=10-(x+6)/2
We move all terms to the left:
(x+3)/3-(10-(x+6)/2)=0
We calculate fractions
x/()+(-(10-(x+6)*3)/()=0
We calculate terms in parentheses: +(-(10-(x+6)*3)/(), so:
-(10-(x+6)*3)/(
We multiply all the terms by the denominator
-(10-(x+6)*3)
We calculate terms in parentheses: -(10-(x+6)*3), so:
10-(x+6)*3
determiningTheFunctionDomain -(x+6)*3+10
We multiply parentheses
-3x-18+10
We add all the numbers together, and all the variables
-3x-8
Back to the equation:
-(-3x-8)
We get rid of parentheses
3x+8
Back to the equation:
+(3x+8)
We get rid of parentheses
x/()+3x+8=0
We multiply all the terms by the denominator
x+3x*()+8*()=0
We add all the numbers together, and all the variables
x+3x*()=0

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