(x+3)/4=(2x+1)/7

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Solution for (x+3)/4=(2x+1)/7 equation: 



(x+3)/4=(2x+1)/7

We move all terms to the left:

(x+3)/4-((2x+1)/7)=0

We calculate fractions


x/()+(-((2x+1)*4)/()=0



We calculate terms in parentheses: +(-((2x+1)*4)/(), so:

-((2x+1)*4)/(

We multiply all the terms by the denominator


-((2x+1)*4)



We calculate terms in parentheses: -((2x+1)*4), so:

(2x+1)*4

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

-8x-4

Back to the equation:

+(-8x-4)



We get rid of parentheses

x/()-8x-4=0

We multiply all the terms by the denominator


x-8x*()-4*()=0

We add all the numbers together, and all the variables

x-8x*()=0

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