(x+3)/4=(5-x)/6

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Solution for (x+3)/4=(5-x)/6 equation: 



(x+3)/4=(5-x)/6

We move all terms to the left:

(x+3)/4-((5-x)/6)=0

We add all the numbers together, and all the variables

(x+3)/4-((-1x+5)/6)=0

We calculate fractions


x/()+(-((-1x+5)*4)/()=0



We calculate terms in parentheses: +(-((-1x+5)*4)/(), so:

-((-1x+5)*4)/(

We multiply all the terms by the denominator


-((-1x+5)*4)



We calculate terms in parentheses: -((-1x+5)*4), so:

(-1x+5)*4

We multiply parentheses

-4x+20

Back to the equation:

-(-4x+20)



We get rid of parentheses

4x-20

Back to the equation:

+(4x-20)



We get rid of parentheses

x/()+4x-20=0

We multiply all the terms by the denominator


x+4x*()-20*()=0

We add all the numbers together, and all the variables

x+4x*()=0

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