(x+3)/4=(x+5)/5

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Solution for (x+3)/4=(x+5)/5 equation:



(x+3)/4=(x+5)/5
We move all terms to the left:
(x+3)/4-((x+5)/5)=0
We calculate fractions
x/()+(-((x+5)*4)/()=0
We calculate terms in parentheses: +(-((x+5)*4)/(), so:
-((x+5)*4)/(
We multiply all the terms by the denominator
-((x+5)*4)
We calculate terms in parentheses: -((x+5)*4), so:
(x+5)*4
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
We get rid of parentheses
-4x-20
Back to the equation:
+(-4x-20)
We get rid of parentheses
x/()-4x-20=0
We multiply all the terms by the denominator
x-4x*()-20*()=0
We add all the numbers together, and all the variables
x-4x*()=0

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