(x+3)/4=1-(x+2)/7

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Solution for (x+3)/4=1-(x+2)/7 equation:



(x+3)/4=1-(x+2)/7
We move all terms to the left:
(x+3)/4-(1-(x+2)/7)=0
We calculate fractions
x/()+(-(1-(x+2)*4)/()=0
We calculate terms in parentheses: +(-(1-(x+2)*4)/(), so:
-(1-(x+2)*4)/(
We multiply all the terms by the denominator
-(1-(x+2)*4)
We calculate terms in parentheses: -(1-(x+2)*4), so:
1-(x+2)*4
determiningTheFunctionDomain -(x+2)*4+1
We multiply parentheses
-4x-8+1
We add all the numbers together, and all the variables
-4x-7
Back to the equation:
-(-4x-7)
We get rid of parentheses
4x+7
Back to the equation:
+(4x+7)
We get rid of parentheses
x/()+4x+7=0
We multiply all the terms by the denominator
x+4x*()+7*()=0
We add all the numbers together, and all the variables
x+4x*()=0

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