(x+3)/4=1-(x+2)/7

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Solution for (x+3)/4=1-(x+2)/7 equation: 



(x+3)/4=1-(x+2)/7

We move all terms to the left:

(x+3)/4-(1-(x+2)/7)=0

We calculate fractions


x/()+(-(1-(x+2)*4)/()=0



We calculate terms in parentheses: +(-(1-(x+2)*4)/(), so:

-(1-(x+2)*4)/(

We multiply all the terms by the denominator


-(1-(x+2)*4)



We calculate terms in parentheses: -(1-(x+2)*4), so:

1-(x+2)*4

determiningTheFunctionDomain
-(x+2)*4+1

We multiply parentheses

-4x-8+1

We add all the numbers together, and all the variables

-4x-7

Back to the equation:

-(-4x-7)



We get rid of parentheses

4x+7

Back to the equation:

+(4x+7)



We get rid of parentheses

x/()+4x+7=0

We multiply all the terms by the denominator


x+4x*()+7*()=0

We add all the numbers together, and all the variables

x+4x*()=0

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