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(x+3)/5=(2-x)/3
We move all terms to the left:
(x+3)/5-((2-x)/3)=0
We add all the numbers together, and all the variables
(x+3)/5-((-1x+2)/3)=0
We calculate fractions
x/()+(-((-1x+2)*5)/()=0
We calculate terms in parentheses: +(-((-1x+2)*5)/(), so:We get rid of parentheses
-((-1x+2)*5)/(
We multiply all the terms by the denominator
-((-1x+2)*5)
We calculate terms in parentheses: -((-1x+2)*5), so:We get rid of parentheses
(-1x+2)*5
We multiply parentheses
-5x+10
Back to the equation:
-(-5x+10)
5x-10
Back to the equation:
+(5x-10)
x/()+5x-10=0
We multiply all the terms by the denominator
x+5x*()-10*()=0
We add all the numbers together, and all the variables
x+5x*()=0
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