(x+3)/5=(2x-3)/7

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Solution for (x+3)/5=(2x-3)/7 equation: 



(x+3)/5=(2x-3)/7

We move all terms to the left:

(x+3)/5-((2x-3)/7)=0

We calculate fractions


x/()+(-((2x-3)*5)/()=0



We calculate terms in parentheses: +(-((2x-3)*5)/(), so:

-((2x-3)*5)/(

We multiply all the terms by the denominator


-((2x-3)*5)



We calculate terms in parentheses: -((2x-3)*5), so:

(2x-3)*5

We multiply parentheses

10x-15

Back to the equation:

-(10x-15)



We get rid of parentheses

-10x+15

Back to the equation:

+(-10x+15)



We get rid of parentheses

x/()-10x+15=0

We multiply all the terms by the denominator


x-10x*()+15*()=0

We add all the numbers together, and all the variables

x-10x*()=0

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