(x+3)/5=x-2

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Solution for (x+3)/5=x-2 equation:



(x+3)/5=x-2
We move all terms to the left:
(x+3)/5-(x-2)=0
We get rid of parentheses
(x+3)/5-x+2=0
We multiply all the terms by the denominator
(x+3)-x*5+2*5=0
We add all the numbers together, and all the variables
(x+3)-x*5+10=0
Wy multiply elements
(x+3)-5x+10=0
We get rid of parentheses
x-5x+3+10=0
We add all the numbers together, and all the variables
-4x+13=0
We move all terms containing x to the left, all other terms to the right
-4x=-13
x=-13/-4
x=3+1/4

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