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(x+3)/6=(2x-1)
We move all terms to the left:
(x+3)/6-((2x-1))=0
We multiply all the terms by the denominator
(x+3)-(((2x-1)))*6=0
We get rid of parentheses
x-(((2x-1)))*6+3=0
We move all terms containing x to the left, all other terms to the right
x-(((2x-1)))*6=-3
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