(x+3)/8=1-(x+4)/7

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Solution for (x+3)/8=1-(x+4)/7 equation: 



(x+3)/8=1-(x+4)/7

We move all terms to the left:

(x+3)/8-(1-(x+4)/7)=0

We calculate fractions


x/()+(-(1-(x+4)*8)/()=0



We calculate terms in parentheses: +(-(1-(x+4)*8)/(), so:

-(1-(x+4)*8)/(

We multiply all the terms by the denominator


-(1-(x+4)*8)



We calculate terms in parentheses: -(1-(x+4)*8), so:

1-(x+4)*8

determiningTheFunctionDomain
-(x+4)*8+1

We multiply parentheses

-8x-32+1

We add all the numbers together, and all the variables

-8x-31

Back to the equation:

-(-8x-31)



We get rid of parentheses

8x+31

Back to the equation:

+(8x+31)



We get rid of parentheses

x/()+8x+31=0

We multiply all the terms by the denominator


x+8x*()+31*()=0

We add all the numbers together, and all the variables

x+8x*()=0

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