(x+3)2(2-2x)=3(x+5)-2

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Solution for (x+3)2(2-2x)=3(x+5)-2 equation: 



(x+3)2(2-2x)=3(x+5)-2

We move all terms to the left:

(x+3)2(2-2x)-(3(x+5)-2)=0

We add all the numbers together, and all the variables

(x+3)2(-2x+2)-(3(x+5)-2)=0



We calculate terms in parentheses: -(3(x+5)-2), so:

3(x+5)-2

We multiply parentheses

3x+15-2

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We get rid of parentheses

(x+3)2(-2x+2)-3x-13=0

We add all the numbers together, and all the variables

-3x+(x+3)2(-2x+2)-13=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+3)2(-2x+2)=13

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