(x+3)2+(x-3)2=4

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Solution for (x+3)2+(x-3)2=4 equation:



(x+3)2+(x-3)2=4
We move all terms to the left:
(x+3)2+(x-3)2-(4)=0
We multiply parentheses
2x+2x+6-6-4=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1

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