(x+3)2+(y+5)2=16

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Solution for (x+3)2+(y+5)2=16 equation: 


Simplifying
(x + 3) * 2 + (y + 5) * 2 = 16

Reorder the terms:
(3 + x) * 2 + (y + 5) * 2 = 16

Reorder the terms for easier multiplication:
2(3 + x) + (y + 5) * 2 = 16
(3 * 2 + x * 2) + (y + 5) * 2 = 16
(6 + 2x) + (y + 5) * 2 = 16

Reorder the terms:
6 + 2x + (5 + y) * 2 = 16

Reorder the terms for easier multiplication:
6 + 2x + 2(5 + y) = 16
6 + 2x + (5 * 2 + y * 2) = 16
6 + 2x + (10 + 2y) = 16

Reorder the terms:
6 + 10 + 2x + 2y = 16

Combine like terms: 6 + 10 = 16
16 + 2x + 2y = 16

Add '-16' to each side of the equation.
16 + 2x + -16 + 2y = 16 + -16

Reorder the terms:
16 + -16 + 2x + 2y = 16 + -16

Combine like terms: 16 + -16 = 0
0 + 2x + 2y = 16 + -16
2x + 2y = 16 + -16

Combine like terms: 16 + -16 = 0
2x + 2y = 0

Solving
2x + 2y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.
2x + 2y + -2y = 0 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 = 0 + -2y
2x = 0 + -2y
Remove the zero:
2x = -2y

Divide each side by '2'.
x = -1y

Simplifying
x = -1y

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