(x+3)2=3x+13+3x

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Solution for (x+3)2=3x+13+3x equation: 



(x+3)2=3x+13+3x

We move all terms to the left:

(x+3)2-(3x+13+3x)=0

We add all the numbers together, and all the variables

(x+3)2-(6x+13)=0

We multiply parentheses

2x-(6x+13)+6=0

We get rid of parentheses

2x-6x-13+6=0

We add all the numbers together, and all the variables

-4x-7=0

We move all terms containing x to the left, all other terms to the right

-4x=7

x=7/-4

x=-1+3/4

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