(x+3)2=3x+25+3x

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Solution for (x+3)2=3x+25+3x equation:



(x+3)2=3x+25+3x
We move all terms to the left:
(x+3)2-(3x+25+3x)=0
We add all the numbers together, and all the variables
(x+3)2-(6x+25)=0
We multiply parentheses
2x-(6x+25)+6=0
We get rid of parentheses
2x-6x-25+6=0
We add all the numbers together, and all the variables
-4x-19=0
We move all terms containing x to the left, all other terms to the right
-4x=19
x=19/-4
x=-4+3/4

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