(x+3)=1/3(9x+18)-5

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Solution for (x+3)=1/3(9x+18)-5 equation: 



(x+3)=1/3(9x+18)-5

We move all terms to the left:

(x+3)-(1/3(9x+18)-5)=0



Domain of the equation: 3(9x+18)-5)!=0

x∈R



We get rid of parentheses

x-(1/3(9x+18)-5)+3=0

We multiply all the terms by the denominator


x*3(9x+18)+3*3(9x+18)-5)-(1-5)=0

We add all the numbers together, and all the variables

x*3(9x+18)+3*3(9x+18)-5)-(-4)=0

We add all the numbers together, and all the variables

x*3(9x+18)+3*3(9x+18)=0

Wy multiply elements

3x^2(9+9x(9=0

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