(x+3/2x)+(3x-6/8x)=x/6

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Solution for (x+3/2x)+(3x-6/8x)=x/6 equation: 



(x+3/2x)+(3x-6/8x)=x/6

We move all terms to the left:

(x+3/2x)+(3x-6/8x)-(x/6)=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+x+3/2x)+(+3x-6/8x)-(+x/6)=0

We get rid of parentheses

x+3/2x+3x-6/8x-x/6=0

We calculate fractions

We do not support expression: x^3

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