(x+3/x+1)=(2/x+1)

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Solution for (x+3/x+1)=(2/x+1) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+3/x+1 = 2/x+1 // - 2/x+1

x+3/x-(2/x)-1+1 = 0

x+3/x-2*x^-1-1+1 = 0

1*x^1+1*x^-1 = 0

(1*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+1*x^0) = 0

x^1

x^2+1 = 0

x^2+1 = 0

DELTA = 0^2-(1*1*4)

DELTA = -4

DELTA < 0

x in { } 

x belongs to the empty set

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