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(x+30)(x-11)=0
We multiply parentheses ..
(+x^2-11x+30x-330)=0
We get rid of parentheses
x^2-11x+30x-330=0
We add all the numbers together, and all the variables
x^2+19x-330=0
a = 1; b = 19; c = -330;
Δ = b2-4ac
Δ = 192-4·1·(-330)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-41}{2*1}=\frac{-60}{2} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+41}{2*1}=\frac{22}{2} =11 $
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