(x+31)(x-2)=(x+7)(x+10)

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Solution for (x+31)(x-2)=(x+7)(x+10) equation: 



(x+31)(x-2)=(x+7)(x+10)

We move all terms to the left:

(x+31)(x-2)-((x+7)(x+10))=0

We multiply parentheses ..

(+x^2-2x+31x-62)-((x+7)(x+10))=0



We calculate terms in parentheses: -((x+7)(x+10)), so:

(x+7)(x+10)

We multiply parentheses ..

(+x^2+10x+7x+70)

We get rid of parentheses

x^2+10x+7x+70

We add all the numbers together, and all the variables

x^2+17x+70

Back to the equation:

-(x^2+17x+70)



We get rid of parentheses

x^2-x^2-2x+31x-17x-62-70=0

We add all the numbers together, and all the variables

12x-132=0

We move all terms containing x to the left, all other terms to the right

12x=132

x=132/12

x=11

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