(x+31)+(3x-10)+(2x-3)=180

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Solution for (x+31)+(3x-10)+(2x-3)=180 equation: 



(x+31)+(3x-10)+(2x-3)=180

We move all terms to the left:

(x+31)+(3x-10)+(2x-3)-(180)=0

We get rid of parentheses

x+3x+2x+31-10-3-180=0

We add all the numbers together, and all the variables

6x-162=0

We move all terms containing x to the left, all other terms to the right

6x=162

x=162/6

x=27

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