(x+31)+(3x-10)=150

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Solution for (x+31)+(3x-10)=150 equation: 



(x+31)+(3x-10)=150

We move all terms to the left:

(x+31)+(3x-10)-(150)=0

We get rid of parentheses

x+3x+31-10-150=0

We add all the numbers together, and all the variables

4x-129=0

We move all terms containing x to the left, all other terms to the right

4x=129

x=129/4

x=32+1/4

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