(x+32)(x+50)=2320

Solution for (x+32)(x+50)=2320 equation:

(x+32)(x+50)=2320

We move all terms to the left:

(x+32)(x+50)-(2320)=0

We multiply parentheses ..

(+x^2+50x+32x+1600)-2320=0

We get rid of parentheses

x^2+50x+32x+1600-2320=0

We add all the numbers together, and all the variables

x^2+82x-720=0

a = 1; b = 82; c = -720;
Δ = b2-4ac
Δ = 822-4·1·(-720)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-98}{2*1}=\frac{-180}{2}
=-90
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+98}{2*1}=\frac{16}{2}
=8
$