(x+35)/(x)+(x-2)/(3)=1

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Solution for (x+35)/(x)+(x-2)/(3)=1 equation: 



(x+35)/(x)+(x-2)/(3)=1

We move all terms to the left:

(x+35)/(x)+(x-2)/(3)-(1)=0



Domain of the equation: x!=0

x∈R



We calculate fractions


(3x+105)/3x+(x^2-2x)/3x-1=0

We multiply all the terms by the denominator


(3x+105)+(x^2-2x)-1*3x=0

Wy multiply elements

(3x+105)+(x^2-2x)-3x=0

We get rid of parentheses

x^2+3x-2x-3x+105=0

We add all the numbers together, and all the variables

x^2-2x+105=0

a = 1; b = -2; c = +105;
Δ = b2-4ac
Δ = -22-4·1·105
Δ = -416
Delta is less than zero, so there is no solution for the equation

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