(x+4)(2x+4)-x(2x)=136

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Solution for (x+4)(2x+4)-x(2x)=136 equation:


Simplifying
(x + 4)(2x + 4) + -1x(2x) = 136

Reorder the terms:
(4 + x)(2x + 4) + -1x(2x) = 136

Reorder the terms:
(4 + x)(4 + 2x) + -1x(2x) = 136

Multiply (4 + x) * (4 + 2x)
(4(4 + 2x) + x(4 + 2x)) + -1x(2x) = 136
((4 * 4 + 2x * 4) + x(4 + 2x)) + -1x(2x) = 136
((16 + 8x) + x(4 + 2x)) + -1x(2x) = 136
(16 + 8x + (4 * x + 2x * x)) + -1x(2x) = 136
(16 + 8x + (4x + 2x2)) + -1x(2x) = 136

Combine like terms: 8x + 4x = 12x
(16 + 12x + 2x2) + -1x(2x) = 136

Remove parenthesis around (2x)
16 + 12x + 2x2 + -1x * 2x = 136

Reorder the terms for easier multiplication:
16 + 12x + 2x2 + -1 * 2x * x = 136

Multiply -1 * 2
16 + 12x + 2x2 + -2x * x = 136

Multiply x * x
16 + 12x + 2x2 + -2x2 = 136

Combine like terms: 2x2 + -2x2 = 0
16 + 12x + 0 = 136
16 + 12x = 136

Solving
16 + 12x = 136

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 12x = 136 + -16

Combine like terms: 16 + -16 = 0
0 + 12x = 136 + -16
12x = 136 + -16

Combine like terms: 136 + -16 = 120
12x = 120

Divide each side by '12'.
x = 10

Simplifying
x = 10

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