(x+4)(2x-1)/7=0

Solution for (x+4)(2x-1)/7=0 equation:

(x+4)(2x-1)/7=0

We multiply parentheses ..

(+2x^2-1x+8x-4)/7=0

We multiply all the terms by the denominator


(+2x^2-1x+8x-4)=0

We get rid of parentheses

2x^2-1x+8x-4=0

We add all the numbers together, and all the variables

2x^2+7x-4=0

a = 2; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·2·(-4)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*2}=\frac{2}{4}
=1/2
$