(x+4)(2x-1)=(x+2)(2x+1

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Solution for (x+4)(2x-1)=(x+2)(2x+1 equation: 



(x+4)(2x-1)=(x+2)(2x+1

We move all terms to the left:

(x+4)(2x-1)-((x+2)(2x+1)=0

We multiply parentheses ..

(+2x^2-1x+8x-4)-((x+2)(2x+1)=0



We calculate terms in parentheses: -((x+2)(2x+1), so:

(x+2)(2x+1



We get rid of parentheses

2x^2-1x+8x-((x+2)(2x+1)-4=0

We multiply parentheses ..

2x^2-((+2x^2+x+4x+2)-4-1x+8x=0

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