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(x+4)(3x+45)=0
We multiply parentheses ..
(+3x^2+45x+12x+180)=0
We get rid of parentheses
3x^2+45x+12x+180=0
We add all the numbers together, and all the variables
3x^2+57x+180=0
a = 3; b = 57; c = +180;
Δ = b2-4ac
Δ = 572-4·3·180
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-33}{2*3}=\frac{-90}{6} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+33}{2*3}=\frac{-24}{6} =-4 $
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