(x+4)(3x-7)=(3x-8)(x+5)

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Solution for (x+4)(3x-7)=(3x-8)(x+5) equation: 



(x+4)(3x-7)=(3x-8)(x+5)

We move all terms to the left:

(x+4)(3x-7)-((3x-8)(x+5))=0

We multiply parentheses ..

(+3x^2-7x+12x-28)-((3x-8)(x+5))=0



We calculate terms in parentheses: -((3x-8)(x+5)), so:

(3x-8)(x+5)

We multiply parentheses ..

(+3x^2+15x-8x-40)

We get rid of parentheses

3x^2+15x-8x-40

We add all the numbers together, and all the variables

3x^2+7x-40

Back to the equation:

-(3x^2+7x-40)



We get rid of parentheses

3x^2-3x^2-7x+12x-7x-28+40=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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