(x+4)(x+)=x2+6x+8

Solution for (x+4)(x+)=x2+6x+8 equation:

(x+4)(x+)=x2+6x+8

We move all terms to the left:

(x+4)(x+)-(x2+6x+8)=0

We add all the numbers together, and all the variables

-(+x^2+6x+8)+(x+4)(+x)=0

We get rid of parentheses

-x^2-6x+(x+4)(+x)-8=0

We multiply parentheses ..

-x^2+(+x^2+4x)-6x-8=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+4x)-6x-8=0

We get rid of parentheses

-1x^2+x^2+4x-6x-8=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4